Find the tangent line to the curve x-y = 6ey at the point (6,0). 6 (s 1+6e0 016e Find the tangent line to the curve x-y = 6ey at the point (6,0). 6 (s 1+6e0 016e
5. (6) Find the equation of the line tangent to the curve y = f(x)=x* –2x+1 at the point (2, 13) and use it to estimate f (2.01).
Find the equation of the tangent line to the curve y = 6 sinx at the point (π/6, 3). The equation of this tangent line can be written in the form y = mx + b where m = _______ and b =
13) Find an equation of the tangent line to the curve y=sin(5x)+cos(8x) at the point (π/6,y(π/6)). what is the tangent line: 14) f(x)=4x^2cos(4x) what is the first and second derivatives and solve both for F(5) NOTE There should be four answers! 16) Suppose that f(x)=3x/(4−5x^)3 find an equation for the tangent line to the graph of f at x=2. the tangent line: y=
Find the equation of the line that is tangent to the curve y = 4x cos x at the point (π,-4π) The equation of this tangent line can be written in the form y = mx + b where m = _______ and b = _______
Find an equation for the line tangent to the curve at the point defined by the given value oft. Also, find the value of dy at this point x=++ cost, y = 1 + 2 sin tt-7 Write the equation of the tangent line. y=-x+ (Type exact ahswers, using as needed)
Find an equation of the tangent line to the curve at the given point. y = x4 + 5x2 - x, (1,5) y = Show My Work (Requiredi 2
Find an equation for the line tangent to the curve at the point defined by the given value of t. x = sin t, y = 2 sin t, t = wa y = 2x - 213 y = 2x y = 2x + 13 Oy=-2x+ 2/3 Find an equation for the line tangent to the curve at the point defined by the given value of t. x=t, y= V2t, t = 18 y=- X-3 y=+x+3 O y = 1...
d²y Find an equation for the line tangent to the curve at the point defined by the given value of t. Also, find the value of at this point dx x= 16 cost. y = 4 sint, t = 7 л 2 The equation represents the line tangent to the curve att (Type an exact answer, using radicals as needed.) dy The value of att is dx? (Type an exact answer, using radicals as needed.) 70 4
At the given point, find the slope of the curve or the line that is tangent to the curve, as requested. y® + x3 = y2 + 11x, tangent at (0,1) 11 O A. y=- 8 11 OB. y=- EX-1 11 O C. y= 6*+1 11 OD. y= *+1
The equation of this Find the equation of the tangent Line to the curve y = 6 tan z at the point (536). tangent line can be written in the form y = mx + b where mis: and where bis: