Solve the following problem using the Simplex-Method-and show the dictionaries and code in AMPL. subject to 5; x, +2x, +3x, subject to x,+x, +2x, s3; subject to x,.x2,r, 20; Solve the following...
Solve the linear programming problem using the simplex method. Maximize z = 2X, + 5x, subject to 5x, + X560 5x + 2x2 580 X1 + x2 $70 X1, X2 20. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. The maximum is z = when X, x2 = 1,5, - S2 = and s3 = B. There is no maximum solution for this linear programming problem.
Solve the following problem using the Simplex-Method and show.the.AMPL.code. subject to xi +x2 +x3 s12; subject to2x, +x2 +3xz 318; subject to Solve the following problem using the Simplex-Method and show.the.AMPL.code. subject to xi +x2 +x3 s12; subject to2x, +x2 +3xz 318; subject to
Excel Use Simplex method and Exel To solve the following LPPs. Maximize Maximize P-3x + x2 subject to the constraints x1 + x2 = 2 2x) + 3x2 s 12 3x + = 12 x 20 x220 P = 5x1 + 7x2 subject to the constraints 2xy + 3x2 = 12 3x + x2 = 12 x 20 *2 2 0 Maximize Maximize P = 2x2 + 4x2 + x3 subject to the constraints -*1 + 2x2 + 3x3 5...
Solve by using the SIMPLEX method. Show all steps please. Thank you! min s.t. F(x)= 3x, – x2 g(x)=-4x2 + x2 50.5 g(x)= x2 + x2 56 g(x) = 3x, -X, 21 X2,4220 min s.t. F(x)=-3x, +xz g(x) = 0.5x, +xz 56 82(x)=-2x, +x, 2-5 h(x)= 0.5x4 – x2 = 1 ,42 30 min s.t. F(x) = 3x2 + x2 81(x) = 3x2 + x2 23 82(x)= x;/4+xz 21 83(x)=-2x, +xz 52 X1,4, 20
*5. Solve the following LP problem using two-phase Simplex method: Maximize f= 4x1+ x2 + x3 subject to: 2x1x22x3= 4 Зх1 +3x2 + хз %3D 3, X12 0, х2 20, х3 2 0. [Note: Since a BFS is not available, start Phase I simplex algorithm by introducing variables] two artificial *5. Solve the following LP problem using two-phase Simplex method: Maximize f= 4x1+ x2 + x3 subject to: 2x1x22x3= 4 Зх1 +3x2 + хз %3D 3, X12 0, х2 20,...
samplex Problem1: Solve the following problem using simplex method: Max. z = 2 x1 + x2 – 3x3 + 5x4 S.t. X; + 7x2 + 3x3 + 7x, 46 (1) 3x1 - x2 + x3 + 2x, 38 .(2) 2xy + 3x2 - x3 + x4 S 10 (3) E. Non-neg. x > 0, x2 > 0, X3 > 0,44 20 Problem2: Solve the following problem using big M method: Max. Z = 2x1 + x2 + 3x3 s.t. *+...
*5. Solve the following LP problem using two-phase Simplex method: Maximize f- 4x1x2 X3 subject to 2х1 + X2 + 2хз - 4, Зх1 + 3x2 + хз 3 3, х120, х2 2 0, хз 2 0. Note: Since a BFS is not available, start Phase I simplex algorithm by introducing two artificial variables] *5. Solve the following LP problem using two-phase Simplex method: Maximize f- 4x1x2 X3 subject to 2х1 + X2 + 2хз - 4, Зх1 + 3x2...
SIMPLEX METHOD Solve the following problem using simplex method LP MODEL Let X1 no. of batches of Bluebottles X2 no. of batches of Cleansweeps Objective: Max Z-10X1+20X2 Subject to: 3X1 4X2 S 3 Plant 1 assembly capacity constraint -X1 2-5 5X1 +6X2 s 18 Z, X1, X2 20 Plant 2 capacity constraint Plant 3 capacity constraint
Maximize z = 3x, + 2x, subject to 6.x, +4x2 = 24 Solve the linear programming with Simplex Method. 10x, +3x, s 30 x,x220
Solve the linear programming problem using the simplex method Maximize P=2x2 + 3x2 + 4x3 subject to X1 + x3 s 12 X2 + x3 s 9 *2, X2, X3 20 Use the simplex method to solve the problem. Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. O A. The maximum value of Pis when xy = X2 and x3 = OB. There is no optimal solution