Question

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Problem 4 Express the field below in cylindrical and rectangular components rr2

Answer 1

Given But we know 1 Normallv a vector field should be Ρ.cos6--.r: ýc2 +),2+:2 Sin Θ Comparing (1) and (2), gives Substituting values gives, ) ( )( )- 141 Now 0 Converting spherical coordinate svstem to rectangular system as cose cose -sin θ

Az Ap or Hence field vector E in rectangular coordinate system IS Hence field vector E in cylindrical coordinate system i Now, for cylindrical coordinate system IS sines P.cose =一.r=./r2 +3,2 + :2

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