Using Python to solve the question
def _put(self,key,val,currentNode):
if key < currentNode.key:
if currentNode.hasLeftChild():
self._put(key,val,currentNode.leftChild)
else:
currentNode.leftChild = TreeNode(key,val,parent=currentNode)
elif key > currentNode.key:
if currentNode.hasRightChild():
self._put(key,val,currentNode.rightChild)
else:
currentNode.rightChild = TreeNode(key,val,parent=currentNode)
Here is the modified code for this method. Assuming the value of a node is stored in an instance variable named val. If it is anything else, update it with that name as needed. (Since you did not provide the complete existing code, I could only guess). Comments are included, go through it, learn how things work and let me know if you have any doubts or if you need anything to change. If you are satisfied with the solution, please rate the answer. Thanks
def _put(self,key,val,currentNode):
#checking if key is equal to current node's
key
if key ==
currentNode.key:
#replacing current
node's value to val. Assuming value is stored
#in instance variable
called val. If it is anything different, then
#replace val with
that
currentNode.val=val
elif key <
currentNode.key:
if
currentNode.hasLeftChild():
self._put(key,val,currentNode.leftChild)
else:
currentNode.leftChild = TreeNode(key,val,parent=currentNode)
elif key >
currentNode.key:
if
currentNode.hasRightChild():
self._put(key,val,currentNode.rightChild)
else:
currentNode.rightChild = TreeNode(key,val,parent=currentNode)
Using Python to solve the question def _put(self,key,val,currentNode): if key < currentNode.key: if currentNode.hasLeftChild(): self._put(key,val,currentNode.leftChild) else: currentNode.leftChild...
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