In mathematics, change of base can mean any of several things:
Number in Different Bases
Changing to base 10 from another base
When we write a normal (base 10) number, like 5763, we mean the value:
5000+700+60+3
or, to put it in a more revealing form:
5⋅103+7⋅102+6⋅101+3⋅100
Notice, the "digits" of our number correspond to the coefficients on the powers of ten that are added together to obtain the value of our number.
In a similar manner, we can specify numbers in other "bases" (besides 10), using different digits that correspond to the coefficients on the powers (of the given base) that must be added together to obtain the value of our number.
For example, the "base 8" (or "octal") number (as indicated by the subscript)
5763(8)
equals
5⋅83+7⋅82+6⋅81+3⋅80=3059
For smaller bases, we use a subset of these digits. For example, in base 5, we only use digits 0-4; in base 2 (which is also called binary), we only use the digits 0 and 1.
For larger bases, we need to have single digits for values past 9. Hexadecimal (base 16) numbers provide an example of how this can be done. In hexadecimal, we use digits 0-9 and A-F, where A=10, B=11, C=12, D=13, E=14, and F=15. In this way, we have digits corresponding to 0-15, which is what we need.
Changing from base 10 to a different base
One (straight-forward, but inefficient) way to convert from base 10 to a different base is to:
For example, to convert 1073 to base 5, we recall that:
50 = 1 51 = 5 52 = 25 53 = 125 54 = 625 55 = 3125
Then we notice that 54 = 625 is the highest power of 5 under 1073.
1073 = 1 * 625 + 448 448 = 3 * 125 + 73 73 = 2 * 25 + 23 23 = 4 * 5 + 3 3 = 3 * 1 + 0
The bold digits, 13243, reveal the base 5 representation of 1073.
This process, however, is inefficient in that one must both know and use the various powers of the desired base.
There is a simpler way!
Consider the remainders seen upon division of the following numbers by 5:
1073 = 214 * 5 + 3 214 = 42 * 5 + 4 42 = 8 * 5 + 2 8 = 1 * 5 + 3 1 = 0 * 5 + 1
Note: the base 5 representation comes from reading off the
remainders (in red) from bottom to top!
In each step above, we are just dividing by 5 and looking at both
the quotient and remainder -- no knowledge of higher powers of 5 is
necessary!
Wonderfully, this technique works in any base. (Can you explain why?)
So, for example, if we wanted to find the binary (base 2) representation of 1000, we simply calculate the following:
1000 = 500 * 2 + 0 500 = 250 * 2 + 0 250 = 125 * 2 + 0 125 = 62 * 2 + 1 62 = 31 * 2 + 0 31 = 15 * 2 + 1 15 = 7 * 2 + 1 7 = 3 * 2 + 1 3 = 1 * 2 + 1 1 = 0 * 2 + 1
So 1000 in binary is 1111101000
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