6a)
Width of web of concrete=5"
Effective depth=19"
Grade if concrete=4000 psi
Shear strength of concrete alone=0.75*2*sqrt(4000)*5*19/1000=9 kips
Grade of steel=60 ksi
Number of legs of #3 stirrups=2
Area of stirrups =2*0.11=0.22 in²
Spacing of stirrups=10"
Design strength of stirrups=0.75*60*0.22*19/10=28.7
Total design shear strength of section=9+28.7=37.7 kips
b)
Width of web=6+6=12 in
Effective depth=19.5 in
Shear strength of concrete=0.75*2*sqrt(4000)*12*19.5/1000=22.2 kips
Area of stirrups=2*0.2=0.4 in²
Spacing=12 in
Desugn strength of stirrups=0.75*60*0.4*19.5/12=29.25 kips
TotsT strength of section=22.2+29.25=51.45 kips
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