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Ca(OH)2 is added to water to reach a concentration of 53 mg/L. Initially, the water had 3.09 mg/L of Mg2+ and it reacts...

Ca(OH)2 is added to water to reach a concentration of 53 mg/L. Initially, the water had 3.09 mg/L of Mg2+ and it reacts with Ca(OH)2 according to equation below. Assume SO4-2 is in excess. What are the final dissolved Ca2+and Mg 2+ concentrations? What is the initial and final hardness? What is the Mg(OH)2 precipitate concentration? Answer should be (28.6 mg/L, 0 mg/L, 12.5 mg CaCO3/L, 71.5 mg CaCO3 /L, 7.28 mg/L).

Mg2+ + SO42- + Ca(OH)2 = Mg(OH)2 +Ca2+ +SO42-

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solution: 53 IL Ca (OH oddad Amount making scution a basie moleculor roa of ca COHD2 =14 mat So mole o05314 o.co0T1ola FROCunOllt cat 2 ui all mg+2 fivally consumod and be ove o.0co11 x 100 mL mola of ma couS2 Pecipitated role of ma+ 2 0.0o01du mee m

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