Question

Ca(OH)2 is added to water to reach a concentration of 53 mg/L. Initially, the water had 3.09 mg/L of Mg2+ and it reacts with Ca(OH)2 according to equation 61a. Assume SO4-2 is in excess. What are the final dissolved Ca2+and Mg 2+ concentrations? What is the initial and final hardness? What is the Mg(OH)2 precipitate concentration? (28.6 mg/L, 0 mg/L, 12.5 mg CaCO3/L, 71.5 mg CaCO3 /L, 7.28 mg/L).Precipitation of noncarbonate Mg, leaving Ca from lime in solution. Mf+ + so,2-+ Ca(OH),-Mg(OH): + Ca2+ + SO42- (61a)

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Answer #1

0 my2t sot?- t exces 2 + ca (0H)2 → my(CH)2.t.ca + so .OS 3 2+-3.09 molari 4- 1600-X24- e maar is Limiting- 寻ent Solution12.L

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