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Calculate the volume of iron replacement containing 5 mg/mL required for a 235 pound patient with a hemoglobin value of...

Calculate the volume of iron replacement containing 5 mg/mL required for a 235 pound patient with a hemoglobin value of 9.1 g/dL.

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Answer #1

Given

Weight 225 pound=102kg

Hemoglobin:9.1g/dl

Haemoglobin iron deficit (mg)=weight (kg)×(14_Hgb)×(2.145)

=102×(14_9.1)×2.145

=499.8×2.145

=1072mg

Total calculate the volume of the product required (ml):weight (kg)×(- 4_Hgb)×(2.145)/C

​ Here C is the concentration of elemental iron present in the product

C=5mg/dl

1072/5

=21417ml is the required volume

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