Question

Question 5 (1 point) If (4.544x10^1) g of oxygen react with (4.81x10^1) g of carbon monoxide to form carbon dioxide. What mass of carbon dioxide forms? Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: X10 Answer

Answer 1

Balanced Reaction will be

2 CO + O2 ==> 2 CO2

Given

4.544 * 10 g O2 ==> moles of O2 = mass of O2/molar mass of O2

= 4.544*10 g/ 32 g/mol

= 1.42 moles

4.81 * 10 g CO ==> moles of CO = mass of CO/Molar mass of CO

= 4.81*10/28 g/mol

= 1.72 moles

From the reaction we can say that

2 moles of CO reacts with 1 mole of O2

So

1.72 moles of CO reacts with 0.86 moles O2

But there are 1.42 moles O2

So

CO is the limiting reactant

Also from the reaction we can say that

2 moles of CO produces 2 moles of CO2

Then

1.72 moles CO will produce 1.72 moles CO2

Mass of CO2 = moles of CO2 * Molar mass of CO2

= 1.72 moles * 44 g/mol

=75.6 g CO2 produced

= 7.56 * 10¹ grams CO2