Molar mass of Si = 28.09 g/mol
mass(Si)= 22.19 g
use:
number of mol of Si,
n = mass of Si/molar mass of Si
=(22.19 g)/(28.09 g/mol)
= 0.79 mol
Molar mass of Cl2 = 70.9 g/mol
mass(Cl2)= 17.7 g
use:
number of mol of Cl2,
n = mass of Cl2/molar mass of Cl2
=(17.7 g)/(70.9 g/mol)
= 0.2496 mol
Balanced chemical equation is:
Si + 2 Cl2 ---> SiCl4
1 mol of Si reacts with 2 mol of Cl2
for 0.79 mol of Si, 1.58 mol of Cl2 is required
But we have 0.2496 mol of Cl2
so, Cl2 is limiting reagent
we will use Cl2 in further calculation
Molar mass of SiCl4,
MM = 1*MM(Si) + 4*MM(Cl)
= 1*28.09 + 4*35.45
= 169.89 g/mol
According to balanced equation
mol of SiCl4 formed = (1/2)* moles of Cl2
= (1/2)*0.2496
= 0.1248 mol
use:
mass of SiCl4 = number of mol * molar mass
= 0.1248*1.699*10^2
= 21.21 g
Answer: 2.12*10^1 g
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