Question

for this experiment, what is the balanced chemical equation and mechanism?

Experimental Procedure a) Reagent Preparation (mix in hood): 1. In a 125mL Erlenmeyer dissolve 1 mL of the sebacyl chloride in 50 mL of hexane. Label the Solution as SC 2. In a 50mL Erlenmeyer dissolve 2.5 mL of 1,6-hexanediamine in 25 mL of 3% sodium hydroxid Label the solution as diamine. (The 3% NaOH solution will be provided) b) Nylon Synthesis 1. Using a 10mL graduate cylinder take 10 mL of the diamine solution and place in a beaker (50mL or 100mL) 2. Carefully and gently pour 20 mL of the SC solution over the diamine solution so as to form two layers. This can be accomplished by pouring down the side of the beaker using a Pasteur pipet or a glass stirring rod. 3. Reach to the interface with tweezer or a spatula to grasp the polymeric film, and SLOWLY withdraw it from the beaker. Using a glass stir rod or a large test tube, WIND the nylon rope until one of the reagents is exhausted. SLOW pulling will help to avoid incorporating of the solutions into the nylon rope. You can overlap the rope on the glass rod. 4. Using a squirt bottle, wash the product first with water and then with Acetone to speed the drying as well as to remove more of the reagents. Leave the polymer drying for at least 1h 5. Measure the rope when you are done (you may want to go out into the hallway. Approximately Im of polymer should be obtained by the students). 6. How many meters of nylon rope did you get from your 30 mL of reagent? hexanes containing Monomer 1 :: water containing Monomer 2 water containing

Answer 1

The reaction of sebacoyl chloride and 1 6-hexanediamine give the Nylon 6,10 organic polymer.

Ans m HaN-CnNM2 + m u ,6Hexanediamins Sebacoye chlonole Mechanism e и 92 NM2 - H 2 Nylon 6.10