Question 7 of 9 How many moles of CH3NH3Cl need to be added to 200.0 mL of a 0.500 M solution of CH3NH2 (Kb for CH3NH2...

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Question 7 of 9 How many moles of CH3NH3Cl need to be added to 200.0 mL of a 0.500 M solution of CH3NH2 (Kb for CH3NH2 is 4.4

Answer 1

Answer #1

pou= 14- pH - 14 - 11.60 - 2.40 K = 4.4010 pkb = -log kb = -log (4.4x104) = 3.356 - CH₂ NHgCl = salt CH₂NH₂ = weak bare moler

Answer 2

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