Question

The bevel pinion rotates at 840 rpm in the direction shown and transmits 5.25 kW to the gear. The mounting distances, the loc

0 0
Add a comment Improve this question Transcribed image text
Answer #1

N=840 RPM

P=5.25KW

(a) Forces for bevel gears

     \omega=2\PiN/60= (2\Pi*840)/60= 87.96 rad/s

    T=P*\omega= 5.25*87.96= 461.79Nm

   F(smaller gear)=T/r1= 461.79/52.5= 8.796 N

   F(larger gear)= T/r2=461.79/157.5= 2.932 N

(b) Work done on each bearing of the larger gear

       W=F(larger)* s = 2.932* [(126+84)/2-51]= 158.328 J

      Work done on smaller gear's bearing

      W=F(smaller)* s= 8.796* (105/2)= 461.79 J

(c) After checking the SKF catalogue, roller and ball bearings are most suitable ones.

    

Add a comment
Know the answer?
Add Answer to:
The bevel pinion rotates at 840 rpm in the direction shown and transmits 5.25 kW to the gear. The mounting distances, t...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT