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x+y+z=1000 x<5000 y<4000 z>3000 how many possible solution x,y,z can be ? x,y,z have to be even numbers .. li...


x+y+z=1000
x<5000
y<4000
z>3000
how many possible solution x,y,z can be ?
x,y,z have to be even numbers .. like 4500 or 5650
anyone has any idea on how to solve it ?
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Answer #1

There can not be any solution because the value of z is always greater then 3000 and the sum x+y+z=1000 so there can not be any such solution.

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