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please explain

Bleach is a common household cleaner that removes stains, disinfects, and can be used to whiten clothes. The % ionization cur
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Answer #1

From the given graph, when concentration if OCl- is 50 %, then pH is 7.5

pOH = 14 - pH

pOH = 14 - 7.5

pOH = 6.5

When concentration of OCl- reaches 50%, this means half-equivalence point is reached in titration and pKb of OCl- equals to pOH at that point.

pKb = pOH

pKb = 6.5

Kb = 10-pKb

Kb = 10-6.5

Kb = 3.16 x 10-7

initial concentration of OCl- = 0.67 M

ICE table OCl- (aq) H2O \rightleftharpoons HOCl (aq) OH-
Initial conc. 0.67 M - 0 0
Change -x - +x +x
Equilibrium conc. 0.67 M - x - +x +x

Kb = [HOCl]eq[OH-]eq / [OCl-]eq

3.16 x 10-7 = [(x) * (x)] / (0.67 M - x)

Solving for x, x = 4.6 x 10-4 M

[OH-] = x = 4.6 x 10-4 M

pOH = -log[OH-]

pOH = -log(4.6 x 10-4 M)

pOH = 3.34

pH = 14 - pOH

pH = 14 - 3.34

pH = 10.7

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