Homework Answers
Vapor pressure of limestone = P1 = 125 kPa = 125/101 = 1.238 atm
We know that the Vapor pressure of water at 60°C = P2 = 0.1966 atm
Total pressure = P = P1 + P2 = 1.238 + 0.1966 = 1.4346 atm
Mole % of limestone = x1 = P1*100/P = 1.238*100/1.4346 = 86.3%
Mole % of water vapor = x2 = P2 * 100/P1 = 13.7 % ...Answer
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