Question

2. Determine the maximum number of electrons with the following quantum numbers in bromine (Br). n = 2,1 = 1 n = 4, mı = -1 n = 4, mı = 1, ms = +1/2 iv) mj = 0

please explain the answer

Answer 1

Quantum NUmbers Principal Suantum Number n) Shell of fhe electron in 9Represevnts atom an Azimothal quantum numbY ) qt represevts Sub-shaU alue of 0to n-1 Megnetee quavtum number (m) 9+ represovets obital. Value of 7 - to +Q mi Spin quantem humber (s) er(ms) treprecente rotatton ot elotron in 9t valu either 5 an orbrtal

NOTE: for a aven Spin quaveto m number (m.), Number of electrens 1 for emagnatc quantom numbeY (m,), Plaximum number oPelectron 2. Bromine Atom'c Number 3S -7 2 2S 2P 3 Sp I2 4S3d10 4pS 1 11 -1O 1 n 2 (if) number ote 6 / mi -2 number ot e 2 1n 4, m, ms+ nomber rt e1 ) (neans all S- orbtals) numbes ot e lectrons こ2+2 +24 2=