From bernoulli's theorem we know that
P/rho*g is the pressure head of flowing fluid and h ( height from
the reference) is its potential head
i. for the given problem
when the pump moves fluid from one reservoir to the
another one
useful head requirement = hpump,u
now head shall be used by the pump for the following
two purposes
a. covering the potential head h = zb - za
b. some loss of pressure in the form of pressure head
( the pressure of the fluid shall nor remain constant throughout
the flow) = hl
hence
hpump,u = (zb - za) + hl
ii. given, volume flow rate, r' = 30 L/s = 30*10^-3 m^3/s
h = zb - za = 8 m
also, hl = 11m ( given)
hence
hpump,u = 11 + 8 = 19 m
useful pumping power = hpump,u*g*rho*r'
rho = 1000 kg/m^3
P = 3237.3 W
iii. Pc - Pd = ?
now, from bernoullis theorem
Pc - Pd = rho*g*hl = 107910 Pa
iv. given efficiency, n = 0.7
power drawn = P/n = 4624.714285 W
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