Question

Review | Const A pure gold ring and pure silver ring have a total mass of 15.3 8. The two rings are heated to 70.3 °C and dropped into a 12.8 mL of water at 21.5 C. When equilibrium is reached, the temperature of the water is 23.8°C. Part A What is the mass of gold ring? (Assume a density of 0.998 g/mL for water.) Express your answer to two significant figures and include the appropriate units. Å ROO? Value Units MA - Submit Request Answer Part B What is the mass of silver ring? (Assume a density of 0.998 g/mL for water.) Express your answer to two significant figures and include the appropriate units. : Value O = ? Units MAX - Submit Request Answer

Answer 1

non Gold specific heat 0.129 Ilgo cur Silves specific heat = 0-240 t/goc water specific heal-= 4.184 I/ goc mass of silver -4 mass > of 2 + y gold a = 15.3 = 2 x 0-129 (23.8 - 70-3)) + 18 +0.240 (23.8-70-3) = 4-184 * 7 *0.998 (23-8-21-5) x12-8 = 5-9985 a t 11.164 = 206.485 - 83-5544 3 122-93060

5.94852 +11.16 y = 122.93060 10 13,1 11 2- mass of gold = 4+2642 Y veline ya mass of Silver = 6.0357 ya -) At equilibrium temp of walessui tempi of sings Heat lost by rings = heat gained by watef, si -> Sam SALA
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