Question

Assuming constant pressure, rank these reactions from most energy released by the system to most energy absorbed by the...

Assuming constant pressure, rank these reactions from most energy released by the system to most energy absorbed by the system, based on the following descriptions:

Surroundings get colder and the system decreases in volume.

Surroundings get hotter and the system expands in volume.

Surroundings get hotter and the system decreases in volume.

Surroundings get hotter and the system does not change in volume.

Also assume that the magnitude of the volume and temperature changes are similar among the reactions.

Rank from most energy released to most energy absorbed. To rank items as equivalent, overlap them.

Part B

A mole of X reacts at a constant pressure of 43.0 atm via the reaction

X(g)+4Y(g)→2Z(g),      ΔH∘=−75.0 kJ

Before the reaction, the volume of the gaseous mixture was 5.00 L. After the reaction, the volume was 2.00 L. Calculate the value of the total energy change, ΔE, in kilojoules.

Express your answer with the appropriate units.

ΔE =
0 0
Add a comment Improve this question Transcribed image text
Answer #1
Concepts and reason

System and surroundings are the two terms in thermodynamics that are the parts of the universe. Heat transfer takes place in between the system and its surroundings.

Total energy of the system at constant pressure depends upon the heat absorbed by the system and expansion work done by the system.

Fundamentals

If the surroundings get cooler, it means the system absorbs the energy from surroundings.

If the surroundings get hotter, it means the system releases the energy to the surroundings.

Volume decrease means the system absorbs energy; that means work is done on the system.

Volume increase means the system releases energy and work is done by the system.

According to the first law of thermodynamics, the energy of the system is defined as the sum of the heat involved in the system and work done the system.

ΔE=q+WΔE=ΔHPΔV\begin{array}{l}\\{\rm{\Delta E}}\,{\rm{ = }}\,{\rm{q + W}}\\\\{\rm{\Delta E}}\,{\rm{ = }}\,{\rm{\Delta H - P\Delta V}}\\\end{array}

Surroundings get hotter and the system expands in volume is the most energy-releasing process.

Surroundings get hotter and the system does not change in volume is the second most energy-releasing process.

Surroundings get hotter and the system decrease in volume is the third most energy-releasing process in the given set.

Surroundings get colder and the system decreases in volume is the least energy-releasing process in the given set.

Therefore, the order is

1.Surroundings get hotter and the system expands in volume

2.Surroundings get hotter and the system does not change in volume

3.Surroundings get hotter and the system decreases in volume

4.Surroundings get colder and the system decreases in volume

(B)

Fromthefirstlawofthermodynamics,ΔE=q+WΔE=ΔHPΔVGiven,ΔH=75.0kJP=43.0atmΔV=2L5L=3LΔE=75kJ(43.0atm×3L×101.325JLatm)=61.9kJ\begin{array}{c}\\{\rm{From}}\,{\rm{the}}\,{\rm{first}}\,{\rm{law}}\,{\rm{of}}\,{\rm{thermodynamics,}}\\\\{\rm{\Delta E}}\,{\rm{ = }}\,{\rm{q}}\,{\rm{ + }}\,{\rm{W}}\\\\{\rm{\Delta E}}\,{\rm{ = }}\,{\rm{\Delta H - P\Delta V}}\\\\{\rm{Given,}}\\\\{\rm{\Delta H}}\,{\rm{ = }}\,{\rm{ - 75}}{\rm{.0}}\,{\rm{kJ}}\\\\{\rm{P = }}\,{\rm{43}}{\rm{.0atm}}\\\\{\rm{\Delta V}}\,{\rm{ = }}\,{\rm{2L - 5L}}\,{\rm{ = - 3L}}\\\\{\rm{\Delta E}}\,{\rm{ = }}\,{\rm{ - 75kJ - }}\,\left( {{\rm{43}}{\rm{.0atm \times - 3L \times }}\frac{{{\rm{101}}{\rm{.325J}}}}{{{\rm{L}}\,{\rm{atm}}}}} \right)\\\\\,\,\,\,{\rm{ = }}\,{\rm{ - 61}}{\rm{.9kJ}}\\\end{array}

Ans:

Surroundings get hotter and the system expands in volume>Surroundings get hotter and the system does not change in volume >Surroundings get hotter and the system decreases in volume >Surroundings get colder and the system decreases in volume

Add a comment
Know the answer?
Add Answer to:
Assuming constant pressure, rank these reactions from most energy released by the system to most energy absorbed by the...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A mole of X reacts at a constant pressure of 43.0 atm via the reaction X(g)+4Y(g)→2Z(g),    &nbs...

    A mole of X reacts at a constant pressure of 43.0 atm via the reaction X(g)+4Y(g)→2Z(g),      ΔH∘=−75.0 kJ Before the reaction, the volume of the gaseous mixture was 5.00 L. After the reaction, the volume was 2.00 L. Calculate the value of the total energy change, ΔE, in kilojoules. Express your answer numerically in kilojoules.

  • A mole of X reacts at a constant pressure of 43.0 atm via the reaction X(g)+4Y(g)→2Z(g), ΔH∘=−75.0 kJ Before the reacti...

    A mole of X reacts at a constant pressure of 43.0 atm via the reaction X(g)+4Y(g)→2Z(g), ΔH∘=−75.0 kJ Before the reaction, the volume of the gaseous mixture was 5.00 L. After the reaction, the volume was 2.00 L. Calculate the value of the total energy change, ΔE, in kilojoules.

  • Review Constants Perio A temperature increase for the surroundings mo the reactions released heat energy t...

    Review Constants Perio A temperature increase for the surroundings mo the reactions released heat energy t s negative for the system. I the surroundings gain heat energy, then the syste You may want to review int Determine Part B Amole of Teacts at a constant pressure of 43.0 atm via the reaction X(g) + 4Y()+22(g), AH = -75.0 kJ Before the reaction, the volume of the gaseous mixture was 5.00 L. After the reaction, the volume was 200 L Calculate...

  • Chemical energy is released or absorbed from reactions in various forms. The most easily measurable form of energy comes...

    Chemical energy is released or absorbed from reactions in various forms. The most easily measurable form of energy comes in the form of heat, or enthalpy. The enthalpy of a reaction can be calculated from the heats of formation of the substances involved in the reaction: ΔH∘rxn=ΔH∘f(products)−ΔH∘f(reactants) Entropy change, ΔS∘, is a measure of the number of energetically equivalent microstates introduced into the system during the reaction. The degree of spontaneity of a reaction is represented by the Gibbs free...

  • part a. The air in an inflated balloon (defined as the system) is warmed over a toaster and absorbs 110 J of heat. As it...

    part a. The air in an inflated balloon (defined as the system) is warmed over a toaster and absorbs 110 J of heat. As it expands, it does 79 kJ of work. What is the change in internal energy for the system? Express the energy in kilojoules to two significant figures. part b. When fuel is burned in a cylinder equipped with a piston, the volume expands from 0.235 L to 1.350 L against an external pressure of 1.02 atm...

  • Chemical energy is released or absorbed from reactions in various forms. The most easily measurable form...

    Chemical energy is released or absorbed from reactions in various forms. The most easily measurable form of energy comes in the form of heat, or enthalpy. The enthalpy of a reaction can be calculated from the heats of formation of the substances involved in the reaction: ΔH∘rxn=ΔH∘f(products)−ΔH∘f(reactants) Entropy change, ΔS∘, is a measure of the number of energetically equivalent microstates introduced into the system during the reaction. The degree of spontaneity of a reaction is represented by the Gibbs free...

  • The enthalpy change, ΔH, for a reaction at constant pressure is defined as: ΔH = ΔE...

    The enthalpy change, ΔH, for a reaction at constant pressure is defined as: ΔH = ΔE + PΔV. For which of the following reactions will ΔH be approximately equal to ΔE? Select all that apply. Group of answer choices 2 NO2(g) -> N2(g) + 2 O2(g) Ca(OH)2(aq) + H2SO4(aq) -> 2 H2O(l) + CaSO4(s) C(s) + O2(g) -> CO2(g) None of the above

  • (a) For the combustion of 0.05483 mol of C5H12O(l) at constant pressure and a temperature of...

    (a) For the combustion of 0.05483 mol of C5H12O(l) at constant pressure and a temperature of 25.00oC, we measure that 176.0 kJ of heat is released by the reaction. With this data, what would be the values of ΔH, ΔU, Q, and W for the combustion of 1.000 moles of C5H12O(l) at constant volume and a temperature of 25.00oC? Combustion is the reaction of a substance with O2(g) to produce CO2(g) and H2O(l). (b) We have an unknown liquid. For...

  • Part A: In which reaction is expansion work gained by the system? View Available Hint(s) In...

    Part A: In which reaction is expansion work gained by the system? View Available Hint(s) In which reaction is expansion work gained by the system? A.)CaCO3(s) →CaO(s) + CO2(g) B.)C2H2(g) + 2H2(g) →C2H6(g) C.)NaCl(s) + AgNO3(s) →AgCl(s) + NaNO3(s) D.)H2(g) + Cl2(g) →2HCl(g) Part B: What is the value of the change in internal energy (in kilojoules) for the reaction 2O3(g) → 3O2(g) which has a ΔH° = −286.0 kJ, if the reaction is carried out at constant pressure of...

  • (a) For the combustion of 0.05033 mol of C5H12O(l) at constant pressure and a temperature of...

    (a) For the combustion of 0.05033 mol of C5H12O(l) at constant pressure and a temperature of 25.00oC, we measure that 176.8 kJ of heat is released by the reaction. With this data, what would be the values of ΔH, ΔU, Q, and W for the combustion of 1.000 moles of C5H12O(l) at constant volume and a temperature of 25.00oC? Combustion is the reaction of a substance with O2(g) to produce CO2(g) and H2O(l). (b) We have an unknown liquid. For...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT