By seeing the unit of k, we can say that this is 2nd order reaction.
we have:
[A]o = 0.75 M
[A] = 0.5 M
k = 2.5*10^-3 M-1.min-1
use integrated rate law for 2nd order reaction
1/[A] = 1/[A]o + k*t
1/(0.5) = 1/(0.75) + 2.5*10^-3*t
2 = 1.333 +2.5*10^-3*t
2.5*10^-3*t = 0.6667
t = 2.667*10^2 min
Answer: 267 min
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