Look at the unit of rate constant.
It is L.mol-1.min-1 which is M-1.min-1
This is unit of k for 2nd order reaction.
So, order of reaction is 2
we have:
[A]o = 0.75 M
[A] = 0.25 M
k = 6.00*10^-3 M-1.min-1
use integrated rate law for 2nd order reaction
1/[A] = 1/[A]o + k*t
1/(0.25) = 1/(0.75) + 6*10^-3*t
4 = 1.333 +6.00*10^-3*t
6.00*10^-3*t = 2.667
t = 4.40*10^2 min
= 440 min
Answer: D
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