Question

ANSWERS

Design load at base of column A = 182.00 kN

Design load at base of column D = 172.58 kN

The slab shown below is to carry a characteristic variable load of 2.5 kN/m2. Calculate the design load on the slab (per m2) and use it to determine the UDL on beams AB & CD. From this, calculate the design load at the base of column A. Repeat for column D. Assume slab / beams span to the outer faces of the columns. Take the unit weight of concrete as 23.5 kN/m3 and that for brickwork as 21.6 kN/m. 6. 5 0 2 8 2 0.215 m thick 2.0m brickwork 0.250 m thick R.C. slah 3.0 m 0.35m x 0.3 m R.C. beam 2.5m 0.35m x 0.3 m R.С. column 8.0m 6.0m

Answer 1

DATE Service luad n ab = 0.215 x2XGX21,6,-+- 2..5- 3.661 KMM 6 Xg Design_trad s.4415 k2 s lab = .Sx3.66 Design lead n BeeorAB- (2.5x6+ 0.21SX2X 6x21.6x6XS 2- 49.16 kNm Desn ead bean CD-/25x+0,215x6 x21.6 x 6 x3 + 0.25 X 23 ,XS Juad e cd base of Cltra A Degi 4q:76X6+10.3gox23Sx 0.35x0.3x235 149.28 12.57x1.S STX Design lead at the base o Column D 4.4Sx6+0.SSX0.>x23,5x6.+03SxO, 2- 2 CXS