Question

Calculate the pH of a 0.0132 M solution of arginine hydrochloride (arginine HCI, H,Arg). Arginine has pK, values of 1.823 (pKa), 8.991 (pK2), and 12.01 (pK). 11.14 pH= Calculate the concentration of each species of arginine in the solution. H,Arg2+16.31 x10-12 М [H,Arg) = М 1.88 м HArg] = м [Arg] 0.26

Answer 1

acting as and He Argt ² Hang +47 acting as base x2 ² Harg tot Ą Augt + 110 2 as 11 Argt acting as acld & base, was amphotenc so pH = pkan aplan = 1.823 +8.991 25.407. 2) cut] 10-5-407. 2

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denominator valve Сюс 2 Си*,*<a, Сит) + ca, a, Сн1) { can co <a т се че)? (15 часотчет), ("ча 1-чи x (165-чо?)) - Со -873 6 9-ячі хо 12-ото) 2 соав+ 2 3 4 5 6 - ona x 16" » т 1 - 59 sex to o g i » 1 - 49 |2-3 о чуҡ (63)

[AgAt2] = Chz Argte) a hath (Arginine), a 6.01 +37x1017 xo.0132m 2-30795*1073 = (3-44 x 100m (Heargt 2 L A [Arginine), [LAT} 2 z 2.306747 X10 x 0.01329 2-30795 X 10 - 10.0132m). = 6.011737x10170-0132m2 [3-44x10ml 2307954 1513 [ang) a Arginine), C AD 2 2 1.5x 1023 2-30795xids x 0.0132 2 8.58 x 103 = 8.6 x 10 ml