Part a)
(There is a change in required equation as the given equation is not balanced in hydrogen. Balanced equation has been used in answer).
Part b)
Moles of CH3OH = 1 g/32 g/mol = 0.03125 mol
[CH3OH ] = 0.03125 mol/5 L = 0.00625 M
[O2] = (1 g/32 g/mol) / 5 L = 0.00625 M
[H2] = (1 g/2 g/mol) / 5 L = 0.100 M
Qc = [CH3OH]2/[O2][H2]4
= (0.00625)2/(0.00625)(0.100)4
= 62.5
As Qc is more than Kc, reaction will proceed towards reactants.
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