On reversing the chemical equation, the sign of enthalpy also changes.it becomes opposite.
so in this case it becomes -195.1kJ.
Hence change in enthalpy = -642.1kJ-195.1kK=-837.2kJ
Given the reactions, X(s) + 10,() — XO() AH = -642.1 kJ XCO,(s) — XO(s) + CO.() AH = +195.1 kJ what is AH for this...
Given the reactions, X(s) + O2(g) — XO(s) AH = -664.9 kJ XCO,() - XO(s) + CO2(g) AH = +201.1 kJ what is AH for this reaction? X(s) + 0,(8) + CO2(g) → XCO,(s) KJ AH =
ON LUI IU ? Given the reactions, AH= -715.3 kJ X(s) + O2(g) + XO(s) XCO,(s) + XO(s) + CO, (g) AH = +219.9 kJ what is AH for this reaction? X(s) + 10,(8) + CO2(g) → XCO,(s) AH = about us careers privacy policy terms of use contact us help. e InkJoy 100 101
Given the reactions, X(s) + 0,(8) XO(s) XCO,(s) XO(s) + CO2(g) AH = -561.9 kJ AH = +282.1 kJ what is AH for this reaction? X(s) + 0,(g) + CO,(g) XCO (5) AH=
Given the reactions, AH = -837.1 kJ X(s) + 0,($) — XO(s) XCO,() - XO(s) + CO AH = +367.9 kJ what is AH for this reaction? X(s) + 0,(g) + CO, — XCO,(s) AH =
stion 21 of 25 > Given the reactions, X(s) + O2(g) → XO(s) XCO,(s) + XO(s) + CO2(8) AH = -712.9 kJ AH = +266.3 kJ what is AH for this reaction? X(s) + O2(8) + CO2(g) → XCO,(s) AH- MacBook Air
Given these reactions, X(s) + +0,8) — XO(S) XCO,(s) — XO(s) + CO2(9 what is AH for this reaction? AH = -656.1 kJ/mol AH = +351.7 kJ/mol X(s) +0,() + CO2(g) — XCO,() AHL kJ/mol
Given the reactions, X(s) + 0,(8) — XO(s) AH = -543.9 kJ XCO,(s) - XO(s) + CO,(6) AH = +175.9 kJ what is AH for this reaction? X(s) + 0,() + CO,() — XCO,(s) AH =
Given these reactions, X(s) + 0,() XO(8) XCO,(s) - XO(s) + CO (9) what is AH for this reaction? AH = -759.5 kJ/mol AH = +163.5 kJ/mol X(3) +0,(9) + C0,(0) — XCO,(8) AH= -1100 kJ/mol
Given these reactions, efoex xols)+co,le) xo) AH=-717.3 kJ/mol xCo,() AH-+108.1 kJ/mol what is AHn for this reaction? Number kJ/mol AH= x6)-10,w-co,e) >xCo,)
Given the reactions, - XO(S) AH = -571.5 kJ XCO3(s) — XO(s) + CO2(g) AH = +342.3 kJ what is AH for this reaction? X(s) + 2O2(g) + CO2(g) → XCO3(s) AH =