Question

For the following reaction, show the transient product of one equivalent of reagent adding across the triple bond, and then show the product of a second mole of reagent.

Answer 1

Concepts and reason

The concept used to solve this problem is reduction of alkyne to alkene and alkane.

Hydrogenation, ${{\rm{H}}_2}$ is the reagent used for the reduction of alkyne to alkene and alkane in the presence of platinum or palladium catalyst.

Fundamentals

Hydrogenation of alkene in the presence of platinum or palladium catalyst gives alkane. Hydrogenation of alkyne in the presence of platinum or palladium catalyst gives alkene.

The reaction is as follows:

The reaction is as follows:

Ans:

The product is as follows: