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A 26.0 g sample of chromium (Cr) reacts with sulfur (S) to form 50.0 g of chromium sulfide. Determine the formula for th...

A 26.0 g sample of chromium (Cr) reacts with sulfur (S) to form 50.0 g of chromium sulfide. Determine the formula for the chromium sulfide and the charge on the chromium ion. Show work for all steps.

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Answer #1

moles of cra 26.09 -0.5 moi! SL * mass of sulfur in chromium sulfide = 50-26 - zug a moles of sulfur- eng, = 0.75 32 g mail e

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