Given,
Mean = 104.25,
Median = 92.5,
Mode = 98
Q1 = (84+88)/2 = 86
Q3 = (98+98)/2 = 98
Q = Q3 - Q1 = 98 - 86 = 12
Q^2 = 12 * 12 = 144
Q3 + Q^2 = 98+144 = 242
Q1 - Q^2 = 86-144 = -58
If the data beyond -58 to 242, those are the outliers. In the given data there is no outliers.
There is no data affected by the outlier. The measure of central tendency values are 81, 84, 88, 91, 94, 98, 98, 200 then mean, median, mode are calculated as
Mean = 104.25 Median = 92.5 Mode = 98.
The data set below represents bugs found by a software tester in her product during different phases of testing: 88,84,8...
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