Question

vil. Explain the distinctly different behavior in the conductivity of NC What species are present in each of these substances? and Nella Species Present NaClaq) NaCl(s) vill. What species are present in 0.1 M HCl and 0.1 MNOH solutions? Wrine equations to describe the reactions that yield these species. Species Present Equation HCl(aq) NaOH(aq) 2. Typical lonic Reactions A 0,01 M HCl with 0.01 M NaOH. The relative conductivities of the solutions tested are as fol. lows. 0.01 M HCl/0.01 M NaOH measured in parallel: Mixture measured in parallel:_ Do the reactants exist as molecules or ions? Does the conductivity change indicate the creation of more ions or a decrease in the number of ions? The total ionic equation for the reaction is The net ionic equation for the reaction is Interpret any changes in the conductivity of the solutions, before and after mising. In accor dance with the preceding equations Experiment 10: Tonic and Covalent Bonding: Conductivity of Solutions of Ionic and Covalent Compounds-Report 119

Answer 1

(vii). Sol :-

NaCl (s) in solid state do not form ions, therefore it will not conduct electricity in solid state because of no movement of ions. On the other hand NaCl (aq) in aqueous solution form Na⁺ (aq) and Cl^- (aq) ions, therefore it will conduct electricity due to the movements of the ions.

	Species present
NaCl (aq)	Na+ (aq) and Cl- (aq) ions
NaCl (s)	NaCl (s)

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(viii). Sol :-

HCl (aq) is the strong acid or strong electrolytes and therefore it is completely dissociated into its ions in aqueous solution.

Similarly,

NaOH (aq) is the strong base or strong electrolytes and therefore it is completely dissociated into its ions in aqueous solution.

	Species present	Equation
HCl (aq)	H+ (aq) and Cl- (aq)	HCl (aq) -----------> H+ (aq) + Cl- (aq)
NaOH (aq)	Na+ (aq) and OH- (aq)	NaOH (aq) ---------> Na+ (aq) + OH-​​​​​​​ (aq)