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You add 10.00 ml. of 0.100 M NaOH to 75.00 ml of pure water, and to this mixture you then add 5.00 ml. of 0.100 M HCI. What w
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mban 10.00 ml of 0.100M naoh added to 75 ml of pure wather water tomorro 10 mi = Best od 0.01 mL No of molers present in 0.01→ 0.005 mole base / Lite 1. [OH-] = 0.005 Repla molel litora in de un pH = 14 - POH inglont pH = 14-(-log [OH-]) y pH = 1-6-l

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You add 10.00 ml. of 0.100 M NaOH to 75.00 ml of pure water, and to this mixture you then add 5.00 ml. of 0.100 M H...
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