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TRIAL 1 TRIAL 2 TRIAL 3 TRIAL 4 15-O0 25.00 15.95.00 IS, O0 25.00 IS.00 25.00 Volume of HCl used (mL) Mean molarity of NaOH (
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Answer #1

The question is based on titration of Naoh and HCl. Triall Volume HCl = 15mL Molasite NaoH = 0.0682M Volume NaoH = 17.95mL

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