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5. If you have a mixture of 1 mole of gaseous diatomic bromine (Br2(g)) and 1 mole of gaseous monatomic bromine (Br(g))...
Question 5 (1 point) For the cell diagram Pt(s) | Br2(1) | Br"(aq) || C1-(aq)| Cl2(g)...
Question 5 (1 point) For the cell diagram Pt(s) | Br2(1) | Br"(aq) || C1-(aq)| Cl2(g) | Pt(s) which reaction occurs at the cathode? O 2C1-(aq) --> Cl2(g) + 2e- O 2Br (aq) --> Br2(1) + 2e O Br2(l) +2e --> 2Br (aq) O Cl2(g) + 2Br (aq) --> 2C1-(aq) + Br2(1) O C12(g) + 22 --> 2C1“(aq)
A Reaction is given: ½Br2(l) --> Br(g) Ho = 112kJ/mol The bond enthalpy of Br-Br is 193 kJ/mol A. Formulate the vaporization process of 1 mol bromine Br2(l). B. Calculate the enthalpy of the vapori...
A Reaction is given: ½Br2(l) --> Br(g) Ho = 112kJ/mol The bond enthalpy of Br-Br is 193 kJ/mol A. Formulate the vaporization process of 1 mol bromine Br2(l). B. Calculate the enthalpy of the vaporization process bromine. Show calculations C. Calculate the energy invested \ emitted by the evaporation of 3.2 gr of bromine. Show calculations. (Explain how you determined whether the energy is invested or emitted in this process). D.A Reaction is given: ½H2(g) + ½Br2(l) --> HBr(g) Ho...
26. A mixture 0.500 mole of carbon monoxide and 0.400 mole of bromine was placed into a rigid 1.00-L container and...
26. A mixture 0.500 mole of carbon monoxide and 0.400 mole of bromine was placed into a rigid 1.00-L container and the system was allowed to come to equilibrium. The equilibrium concentration of COBr) was 0.233 M. What is the value of Kc for this reaction? COBr2(g) CO(g) + Br2(g) + 5.23 1.22 1.165 0.858 0.191 E.
26. A mixture 0.500 mole of carbon monoxide and 0.400 mole of bromine was placed into...
26. A mixture 0.500 mole of carbon monoxide and 0.400 mole of bromine was placed into a rigid 1.00-L container and the system was allowed to come to equilibrium. The equilibrium concentration of COBr) was 0.233 M. What is the value of Kc for this reaction? COBr2(g) CO(g) + Br2(g) + 5.23 1.22 1.165 0.858 0.191 E. INSTRUCTIONS: Answer all questions in the question paper provided. SECTION A (Multiple choice) 1. Consider the general reaction 5Br (aq) + BrO; (aq)...
Saved Question 8 (1 point) Saved For the cell diagram Pt(s) | Br2(1) | Br-(aq) ||...
Saved Question 8 (1 point) Saved For the cell diagram Pt(s) | Br2(1) | Br-(aq) || Cl-(aq) | Cl2(g) | Pt(s) which reaction occurs at the anode? O Cl2(g) + 2Br (aq) --> 2C1-(aq) + Br2(1) O Br2(l) +2e --> 2Br" (aq) O 2Br"(aq) --> Br2(I) + 2e O Cl2(g) +2e --> 2014(aq) O 2014(aq) --> Cl2(g) + 2e
Bromine monochloride is synthesized using the reaction Br2(g) + Cl2(g) = 2 BrCl(g) Kp = 1.1...
Bromine monochloride is synthesized using the reaction Br2(g) + Cl2(g) = 2 BrCl(g) Kp = 1.1 x 10-4 at 150 K A 203.0 L flask initially contains 1.070 kg of Br, and 1.115 kg of Cl. Calculate the mass of BrCl, in grams, that is present in the reaction mixture at equilibrium. Assume ideal gas behavior. mass of BrCl: g What is the percent yield of BrCl? percent yield: %
5. For the overall exothermic reaction: H2(g) + Br2(g) → 2HBr(g) the following mechanism was determined:...
5. For the overall exothermic reaction: H2(g) + Br2(g) → 2HBr(g) the following mechanism was determined: fast Equilibrium Step 1: Brz(8) 2Br(g) Step 2: H2(g) + Br(g)_52HBr(g) + H(g) Step 3: H(g) + Br(g) k3 HBr(g) slow fast Use a plot of AH versus Reaction Pathway to illustrate the three step reaction profile.
Consider the following reaction mechanism: 1) Initiation Br2 → 2 Br• 2) Propagation (here a cycle...
Consider the following reaction mechanism: 1) Initiation Br2 → 2 Br• 2) Propagation (here a cycle of two steps) Br• + H2 → HBr + H• H• + Br2 → HBr + Br• 3) Termination 2 Br• → Br2 This reaction is catalyzed by platinum. Wat causes the bromine to split in the initiation step? Does the platinum influences this or is it just due the weak bonding between Br-Br?
(6 marks) An easy way to analyse the amount of CO2 in a gaseous mixture of CO2 and CO is to pass the gaseous mixture through an aqueous solution that contains excess Ba(OH)2. The CO2 will react...
(6 marks) An easy way to analyse the amount of CO2 in a gaseous mixture of CO2 and CO is to pass the gaseous mixture through an aqueous solution that contains excess Ba(OH)2. The CO2 will react yielding a precipitate of BaCOs but the CO does not react (you will learn why in higher classes). The aforementioned method was used to analyse the equilibrium composition of the gas evolved when 1.77 g of CO2 reacted with 2.0 g of graphite...
# 21. (10 marks) Imagine you react 1.25 g of germanium, Ge(s), with enough liquid bromine, Br2(C), to consume all t...
# 21. (10 marks) Imagine you react 1.25 g of germanium, Ge(s), with enough liquid bromine, Br2(C), to consume all the germanium. The reaction makes 6.75 g of a single solid product with formula Ge, Br, a) (6 marks) Based on this data only (i.e., do NOT use the information given in part (b) yet), what is the empirical formula of the product? Show full calculations. b) (2 marks) If a mass spectrometry experiment determines the product's molar mass to...
Question 5 (1 point) For the cell diagram Pt(s) | Br2(1) | Br"(aq) || C1-(aq)| Cl2(g) | Pt(s) which reaction occurs at the cathode? O 2C1-(aq) --> Cl2(g) + 2e- O 2Br (aq) --> Br2(1) + 2e O Br2(l) +2e --> 2Br (aq) O Cl2(g) + 2Br (aq) --> 2C1-(aq) + Br2(1) O C12(g) + 22 --> 2C1“(aq)
26. A mixture 0.500 mole of carbon monoxide and 0.400 mole of bromine was placed into a rigid 1.00-L container and the system was allowed to come to equilibrium. The equilibrium concentration of COBr) was 0.233 M. What is the value of Kc for this reaction? COBr2(g) CO(g) + Br2(g) + 5.23 1.22 1.165 0.858 0.191 E.
26. A mixture 0.500 mole of carbon monoxide and 0.400 mole of bromine was placed into a rigid 1.00-L container and the system was allowed to come to equilibrium. The equilibrium concentration of COBr) was 0.233 M. What is the value of Kc for this reaction? COBr2(g) CO(g) + Br2(g) + 5.23 1.22 1.165 0.858 0.191 E. INSTRUCTIONS: Answer all questions in the question paper provided. SECTION A (Multiple choice) 1. Consider the general reaction 5Br (aq) + BrO; (aq)...
Saved Question 8 (1 point) Saved For the cell diagram Pt(s) | Br2(1) | Br-(aq) || Cl-(aq) | Cl2(g) | Pt(s) which reaction occurs at the anode? O Cl2(g) + 2Br (aq) --> 2C1-(aq) + Br2(1) O Br2(l) +2e --> 2Br" (aq) O 2Br"(aq) --> Br2(I) + 2e O Cl2(g) +2e --> 2014(aq) O 2014(aq) --> Cl2(g) + 2e
Bromine monochloride is synthesized using the reaction Br2(g) + Cl2(g) = 2 BrCl(g) Kp = 1.1 x 10-4 at 150 K A 203.0 L flask initially contains 1.070 kg of Br, and 1.115 kg of Cl. Calculate the mass of BrCl, in grams, that is present in the reaction mixture at equilibrium. Assume ideal gas behavior. mass of BrCl: g What is the percent yield of BrCl? percent yield: %
5. For the overall exothermic reaction: H2(g) + Br2(g) → 2HBr(g) the following mechanism was determined: fast Equilibrium Step 1: Brz(8) 2Br(g) Step 2: H2(g) + Br(g)_52HBr(g) + H(g) Step 3: H(g) + Br(g) k3 HBr(g) slow fast Use a plot of AH versus Reaction Pathway to illustrate the three step reaction profile.
(6 marks) An easy way to analyse the amount of CO2 in a gaseous mixture of CO2 and CO is to pass the gaseous mixture through an aqueous solution that contains excess Ba(OH)2. The CO2 will react yielding a precipitate of BaCOs but the CO does not react (you will learn why in higher classes). The aforementioned method was used to analyse the equilibrium composition of the gas evolved when 1.77 g of CO2 reacted with 2.0 g of graphite...
# 21. (10 marks) Imagine you react 1.25 g of germanium, Ge(s), with enough liquid bromine, Br2(C), to consume all the germanium. The reaction makes 6.75 g of a single solid product with formula Ge, Br, a) (6 marks) Based on this data only (i.e., do NOT use the information given in part (b) yet), what is the empirical formula of the product? Show full calculations. b) (2 marks) If a mass spectrometry experiment determines the product's molar mass to...
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