The label on a bottle of “organic” liquid fertilizer concentrate states that it contains 8.80 grams of phosphate per 100 mL and that 16 fluid ounces should be diluted with water to make 32 gallons of fertilizer to be applied to growing plants.
The label on a bottle of “organic” liquid fertilizer concentrate states that it contains 8.80 grams of phosphate per 100...
Dilution and Solution .... 03/25/20 ojmooi 4 Question (1 point) DEEP The label on a bottle of "organic" liquid fertilizer concentrate states that it contains 7.20 grams of phosphate per 100.0 ml and that 16.0 fluid Ounces should be diluted with water to make 32.0 gallons of fertilizer to be applied to growing plants. 1st attempt See Periodic Table See Hint What is the phosphate concentration in grams per liter in the diluted fertilizer? (1 gallon = 128 fluid ounces)...
UuDIP LATUL 7 T0 CT 4.22. Hemoglobin in Blood A typical adult body contains 6.0 L of blood. The hemoglobin content of blood is about 15.5 g/100.0 mL of blood. The approximate molar mass of hemoglobin is 64,500 g/mol. How many moles of hemoglobin are present in a typical adult? bottle of "organic" liquid *4.34. Mixing Fertilizer The label on a fertilizer concentrate states that it contains 8 g of phosphate per 100.0 mL and that 16 fluid ounces should...
8/30/2018 Dosage Forms Pharmaceutical calculations Anne Chapter 1 Practice Problems 1. If an insulin injection contains 100 units originemine, how many milliers should be injected to receive 40 units of insulin 2. An injection contains me of medicati in each militer (ml). If a physician prescribes dose or 0.5 mg to be administered to a hospital patient three times daily, how many of injection will be required over a 5-day period? 3. In a clinical study, a drug produced drowsiness...
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Length 1 km = 1,000 m 1m = .001 km 1m = 100 cm 1 cm = .01 m Weight 1 kg = 1,000 1g-,001 kg 1g - 100 g 1 cg=.018 18 = 1,000 mg 1 mg = .001 g Volume 1 kL = 1,000 L 1L = .001 Ki 1L = 100 CL 1 cl = .01L 1 L = 1,000 mL 1 mL = .001 L 1 mm = .001...
The table filled is the lab run.
Please can you use the three informations provided above to answer
the empty table
Take Density of vinegar = 1.005g/mol
concentration of NaOH = 0.1205M
Experiment #7. Titration of Vinegar Goals 1. To determine the mass percent of acetic acid in a solution via titration. 2. To master the technique of titration. Introduction Vinegar is a common household item that is found in a number of products from salad dressing to cleaners. Vinegar...
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PROCEDURE PART I: DILUTING THE VINEGAR SOLUTION The vinegar solution must be diluted by a factor of 5 to be suitable for titration. 1. Obtain - 20 ml of the stock vinegar solution from the fume hood. 2. Using the 10-ml. pipet, pipet" 10 mL of the stock solution to a 50-ml volumetric flask. 3. Fill the volumetric flask to the calibration line with distilled water. Be sure not to go over...
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Pre-Lab Questions: 1. What is the definition of an 'equivalence point' in an acid/base titration? (1 point) 2. In part one of the experiment, you will prepare the acid solutions being titrated from a stock solution. Describe how you will accurately prepare 10.00 mL of 0.100 M HCl solution using a 1.00 M HCI stock solution. In your response to this question, be very specific about the quantities of stock solution and...
1. What is the definition of an 'equivalence point' in an acid/base titration? (1 point) 2. In part one of the experiment, you will prepare the acid solutions being titrated from a stock solution. Describe how you will accurately prepare 10.00 mL of 0.100 M HCl solution using a 1.00 M HCl stock solution. In your response to this question, be very specific about the quantities of stock solution and deionized water to be used in the dilution and the...
The following primary standards can be used for the standardization of bases except. a. Benzoic acid b. Oxalic acid c. CaCO3 d. KHP A solution that may contain NaOH, Na 2CO3, and NaHCO3, alone or in compatible combination was titrated with 0.1200 M HCl. The volume of the acid required to reach the phenolphthalein endpoint was 25.67 mL while 38.13 mL to reach the methyl red endpoint. What are the components of the mixture? a. Na2CO3 only b. NaOH only...