Question 16 of 20 Submit Using the provided table, determine the enthalpy for the reaction C3H2 (g) + 5 O2 (g) → 3...

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Question

Answer 1

Answer #1

C3H8(g) + 5O2(g) --------> 3CO2(g) + 4H2O(g)

∆H°_rxn = $\sum$ n∆H°_f(products) - $\sum$ m ∆H°_f(reactants)

n and m are coefficients of product and reactants

= ( 3mol × ∆H°_f(CO2(g)) + 4mol × ∆H°(H2O(g))) - ( 1mol × ∆H°_f(g)))

standard enthalphy of formation for elements in their standard state is zero , so ∆H°_f is zero

= (3mol × -393.5kJ/mol + 4mol × 241.8kJ/mol ) - ( 1mol × -108.4kJ/mol

= (-2147.7kJ) - ( - 108.4kJ)

= -2039.3 kJ

Answer 2

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