H0rxn = [4H0f(N2) + 3H0f(H2O)] - [2H0f(NH3) + 3H0N2O]
H0rxn = [4(0) + 3(-285.8)] - [2(-46.2) + 3(81.6)]
H0rxn = [-857.4] - [-92.4 + 244.8]
H0rxn = - 1009 . 8 kJ
Question 14 of 14 Submit Using the provided table, determine the enthalpy for the reaction 2...
Question 43 of 50 Submit Using the provided table, determine the enthalpy for the reaction 2 NH3(g) + 3 N20 (g) - 4 N2 (9) + 3 H2O (1) Substance AH (kJ/mol) NH3 (9) -46.2 N20 (g) 81.6 N2 (9) kJ/mol 1 2 3 C +/- : 0 x 100
Question 14 0414 Using the provided table, determine the enthalpy for the reaction 2 NH3 (g) + 3 N20 (g) - 4 N2 (g) + 3 H20 (1) Substance AHI (kJ/mol) NH3(g) -46.2 N20 (9) 81.6 N2 (9) 0 kJ/mol
Question 41 of 50 Submit Using the provided table, determine the enthalpy for the reaction 2 K(s)+2 H20() H2(g) 2 KOH (aq) AHi (kJ/mol) Substance K (s) 0 НаО () -285.8 КОН (ag) -482.4 kJ/mol 1 2 3 4 5 6 С 8 +- 0 x 100 O 7
Question 14 of 20 Submit Using the provided table, determine the enthalpy for the reaction 2 K(s) + 2 H2O(l) → 2 KOH (aq) + H2(g) Substance AH1° (kJ/mol K(s) 0 H2O (1) -285.8 KOH (aq) -482.4 H2 (g)
9. Calculate the enthalpy for the reaction shown below using the provided enthalpies of formation. 2 NH3(g) + 3 N20() ► 4 Nz(s) + 3 H20m Compound N2016 NH3 (8) NOR) AHF (kJ/mol) 81.6 -46.2 90.4 Compound H200 H2018) AHF (kJ/mol) -285.8 -241.8 a. -877.4 kJ b. 321.2 kJ c. 1009 kJ d. -1009 kJ 11 Pinelund in
Question 16 of 20 Submit Using the provided table, determine the enthalpy for the reaction C3H2 (g) + 5 O2 (g) → 3 CO2 (g) + 4 H2O (g) Substance AHF (kJ/mol) C3H8 (9) -108.4 O2 (9) CO2 (g) -393.5 H2O (9) -241.8
Question 42 of 50 Submit Using the provided table, determine the enthalpy for the reaction C(s) + CO2(g) – 2 CO (9) Substance AH (kJ/mol) C (s) 0 CO2 (g) -393.5 kJ/mol 1 2 3 C +/- : 0 x 100
Question 25 of 28 Submit Based on the bond energies for the reaction below, what is the enthalpy of the reaction? HC CH (g)5/2 O2 (g) 2 CO2 (g)+H2O (g) н | с N о Single Bond 432 н c 411 346 305 167 N 386 459 358 201 142 799 C C 602 Multiple CC 835 C O 1072 Bonds 494 615 C N kJ х 1 2 3 4 5 6 C 7 8 +- 0 x 100...
From the given enthalpies of formation, calculate the enthalpy change for the following reaction. Your label should be in kJ/mol. Again, leave a space between the answer and the label. N2H4(0) + 2H2O2(1) ► N2(g) + 4H2O(1) Thermochemical data: Substance AH(kJ/mol). H2O(1) -285.8 N Hall) 50.7 H2O2(1) -187.8 Answer:
At 298 K, evaluate deltaG(kJ) and deltaE (V) for 2CH3OH(l) + 3O2(g) -> 4H2O(g) + 2CO2(g) S (J/mol-K) AH°y (kJ/mol) So (J/mol-K) AH(kJ/mol) Substance Substance N2(g) CH-ОН() 126.8 0 191.5 -238.6 CO(g) NH3(g) 197.9 192.5 -110.5 -46.2 CO2(g) NO(g) 213.6 +90.4 210.6 -393.5 NO2(g) +33.8 240.5 H2(g) HNO3(aq) 130.6 146.0 -206.6 H2O( 69.9 -285.8 O2(g) 188.8 H2O(g) 0 205.0 -241.8