Question

blem 1. A 8.0 m long, non-uniform beam weighing 750 N, supported by two weightless cables, is at rest in horizontal position, as shown. The cable on the right has a tension of Tj-375\3 N. (a) The location of the center of mass of the beam measured from its left end is (b) The tension T2 in the other cable is 60 T2 30 т, fiction). The

Answer 1

T2cos60 - code 12 T2sin 60 8m T1cos30 TA 8m T18in 30

Take moment about the left end

$\sum M=0$

$T_{1}cos30*8m-W*x=0$

$T_{1}cos30*8m=W*x$

$\frac{T_{1}cos30*8}{W}=x$

$\frac{375\sqrt{3}N*cos30*8}{750N}=x$

(a) ANSWER: ${\color{Red} x=6m}$

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Consider all vertical forces

$\sum F_{y}=0$

$T_{2}cos60+T_{1}cos30-W=0$

$T_{2}cos60=W-T_{1}cos30$

$T_{2}=\frac{W-T_{1}cos30}{cos60}$

$T_{2}=\frac{750N-375\sqrt{3}N*cos30}{cos60}$

ANSWER: ${\color{Red} T_{2}=375N}$

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