Question

The mass spec of an organic compound has m/z at 78 amu. The relative intensities of 23.7. The relative intensities of the iso
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Answer #1

Solution:

The molecular formula will be : CH3CH2CH2Cl

Compound is : Propyl chloride

Explanation:

The intersities of isotopic peaks of Cl-35 and Cl-37 are in the ratio of 3 : 1.

The intensities of isotopic peaks of C-12 and C-13 are in nearly 49 : 1.

1) The m/z = 78 is due to C-12 and Cl-35. (CH3CH2CH2Cl)

2) The m/z = 79 is due to C-13 and Cl-35

3) The m/z = 80 is due to C-12 and Cl-37

4) The m/z value of 81 is due to C-13 and C-37.

Therefore,

Structure will be : CH3CH2CH2Cl

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