Question

can someone help me with this question please

sphate, Cas(PO4)2 is 7.7*10* g/dm9 at 25 °C. cu doility product at this temperature. Give your answer in mol/dm. 2. A buffer solution was made up of ammonia and water which produced ammonium ions and hydroxide ions. This solution initially contained 1.00 M of ammonia and 0.400 M of ammonium chloride (K. = 5.62 x10-10 M) a. Write the equilibrium equation which represents this buffer and the simplified K, expression b. Assuming that the ammonium ion is weakly acidic, behaves like an acid and will dissociates into its ions. Write the K, expression, calculate the initial pH and the pk, of this buffer solution c. Calculate the effect on the pH of adding () 5.00 cm of 10.0 M hydrochloric acid and (ii) 5.00 cm of 10.0 M sodium hydroxide solution to 1000 cm of the buffer solution Reactants B and C were mixed to form product ere mixed in a container of uilibrium there

Answer 1

NH3 + H2O - NHA + Hoog hoz. INH4+ 7 TOHJ WH31 H2OJ. NHAT + oH - NH₃ + H₂O Kia {NH] { Hao] TNHAT I TOHI pH z pka tleg I bare I co o ano PH 2 pha t lag [base] sa ng Balt Taid] ro base 2 [NH 3] 31.oom...p HI Acid 2 WHAT 20.4M. pka z - log (5.62X20-10) 29.25. pH = log (5.62x10-10) + lag og 2.9.64 5cm3 of 10M Hel. IBM , 5 cm3 0.005 L 0.0056 No of moles of H 2.0.05 m. e>

Hence the egun becomes Ntly + H+ NH4t 1.M. 0.05. 0.44. -0.05 -0.05 to ob 0.00.45 0.950 pH = Lorele 0.95 11: 9.25+ logo 0.45 ZHAF 9:57. b) 5 an3 of wast of 10.M. moles of Nach z 10.40.05 to 20.05 M. Hence the new equu. NHAT tot - NH₃ + H₂O. 0.40 oograda. 1 m. vg He 0.05 -0.05 0.05 0.35 0. 7.obr. lly PH a 9.25 f. Ful.05 7 6.35. .: 29.12 )