How many milliliters of 0.0200 M Ca(OH)2 are required to neutralize 75.0 mL of 0.0300 M HCI?

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Answer 1

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Answer #1

Ans Molarity of Hel (Mi) = 0.03 M volume of HCI (VI) = 75 mL Molarity of Ca (OH)₂ (M2) = 0,02m let volume of Ca (OH)₂ = V₂ mL

Answer 2

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