Question

1 and 2. A student carried out the procedure described in this experiment to verify Charles's Law. The follow data were obtained: Temperature of the boiling water = 99.0°C Room temperature = 28.0°C Volume of water drawn back into the flask = 50.0mL Total volume of the flask = 275.5mL Identify V, and T, Identify V2 and T2 Using the same equation you used on the Report Sheet, verify Charles's Law. Calculate any percent deviation.

Answer 1

Charles's law : V1 /T1 = V2/T2 or V1*T2 = V2*T1

from given data :

T1= 28 C or 301.15 K

V1 = 50 ml = 0.05 L

T2 = 99 C or 372.15 K

V2 = 275.5 ml = 0.2755 L

using chales law :

V1 /T1 = (0.05 L/ 301.15 K ) = 1.66*10^-4 L/K

V2 /T2 = (0.2755 L/ 372.15 K ) = 7.40*10^-4 L/K

% deviation : (of 1 from 2) =

= I5.74*10^-4 ​​​​​​​L/K I / 7.4 *10^-4 ​​​​​​​L/K * 100 = 77.56 %