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12) Write an equation for the dissociation of ethylene, C2H4. Hint: does ethylene dissolve in water? 13) If 0.24 g of a gas d
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Answer #1

SOLUTION:

PART 12:

The reaction is given by:

C2H4 + H2O + C2H5OH

PART 13:

According to Henry's law, At constant temperature, pressure of a gas is directly proportional to the solubility of the gas.

S = KH.P

Given that,

Pressure, P = 1.5 atm.

Solubility of gas, S = 0.24 g/L.

Therefore, Henry's constant is given by:

S 0.24 g/L -0.16 g/L.atm Ky = = = 1.5 atm

Therefore, Solubility of gas at 6 atm is given by:

S = Ky.P=0.16 g/L.atm x 6 atm

::S=0.96 g/L

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