Given:
Pi = 3.0 atm
Pf = 0.95 atm
Vi = 2.1 mL
Ti = 25.0 oC
= (25.0+273) K
= 298 K
Tf = 25.0 oC
= (25.0+273) K
= 298 K
use:
(Pi*Vi)/(Ti) = (Pf*Vf)/(Tf)
(3 atm*2.1 mL)/(298.0 K) = (0.95 atm*Vf)/(298.0 K)
Vf = 6.63 mL
Answer: 6.63 mL
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