A spherical bubble rises from the bottom of a lake whose temperature is 10 oC at...
A spherical bubble rises from the bottom of a lake whose temperature is 10 oC at the bottom and 22 oC at the surface. If the bubble doubles its volume by the time it reaches the surface, how deep is the lake? (please be specific on how you calculate the volume.)
Homework Answers
T1 =10 oC = 10+273 = 283 K
T2 = 22 oC = 22+273 = 295 K
V1 = 2V2
P1 = 1atm = 1.01*10^5 N/m^2
From ideal gas equation
PV = nRT
P2V2/P1v1 = T2/T1
P2/(2*1.01*10^5) = 295/283
P2 = 2.11*10^5 N/m^2
density of water d =1000 kg/m^3
P2 -P1 = dgh
(2.11-1.01)*10^5 = 1000*9.8*h
h =11.22 m
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