Use the Nernst euation and the cell potential for the Pb-PbI2 cell and the known [Pb2+] to calculate the [Pb2+] in equ...
Use the Nernst euation and the cell potential for the Pb-PbI2 cell and the known [Pb2+] to calculate the [Pb2+] in equilibrium with PbI2.
The measured avgerage cell potential of Pb-PbI2 is 0.084 V
the known [Pb2+] is 0.050 M
Eo of Pb2+ (aq) + 2 e- --------> Pb(s) is -0.13 V
0.050 M KI
Mixed 9 mL of 0.050 M KI with 3 mL of 0.050 M Pb(NO3)2
.
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Use the Nernst euation and the cell potential for the Pb-PbI2 cell and the known [Pb2+] to calculate the [Pb2+] in equ...
Calculating the [PB2+] in a voltaic Pb-PbI2 cell using the recorded cell potential
a concentration cell was made by putting 5 mL of 0.050 M Pb(NO3)2 solution into one half-cell in a test plate. for the neighboring well in the test plate, weplaced 5 mL of a PbI2 solution that was made by mixing 9 mL of 0.050 KI solution with 3 mL of 0.050 M Pb(NO3)2 solution inside. Pb Electrodes were placed in eachcell, and a KNO3-soaked string was used as the salt bridge.data was collected and we recorded the average cell...
EXPERIMENT 1: List the measured potential for Cell 3: Zn|Zn(NO3)2 || Pb(NO3)2|Pb. Based on your observations,...
EXPERIMENT 1: List the measured potential for Cell 3: Zn|Zn(NO3)2 || Pb(NO3)2|Pb. Based on your observations, do you expect given electrochemical cell to be spontaneous or nonspontaneous? Explain your answer. Pb|Pb(NO3)2||Zn|Zn(NO3)2 EXPERIMENT 1: What would happen to the measured cell potentials if 30 mL solution was used in each half-cell instead of 25 mL? EXPERIMENT 1: Calculate the theoretical standard cell potential for the electrochemical cell that includes the reaction. Mn+Pb2+⟶Mn2++Pb The standard reduction potentials for each half reaction are...
The standard reduction potential of the Pb2+|Pb electrode is –0.13 V and the standard potential of...
The standard reduction potential of the Pb2+|Pb electrode is –0.13 V and the standard potential of the cell Zn(s) | Zn2+(aq) || Pb2+(aq) | Pb(s) is +0.63 V. What is the standard reduction potential of the Zn2+|Zn electrode? Question 9 options: –0.76 V –1.52 V +0.76 V –0.50 V +0.50 V
In the following cell, A is a standard Pb2+|Pb electrode connected to a standard hydrogen electrode....
In the following cell, A is a standard Pb2+|Pb electrode connected to a standard hydrogen electrode. For this cell the voltmeter reading is -0.13 V. What is the chemical equation for the cell reaction? Given: Standard reduction potential of the H+/H2 and Pb2+/Pb couples are 0.00 and -0.13 V, respectively. voltmeter saltbridge 1+ Pl(s) LPH2 (g) O Pb2+(aq) + H2(g) --> Pb(s) + 2H+(aq) O Pb(s) + 2H+(aq) --> Pb2+(aq) + H2(g)
Calculate the equilibrium constant, K, at 298 K for the cell: Pb |Pb2+ || Ag+ |...
Calculate the equilibrium constant, K, at 298 K for the cell: Pb |Pb2+ || Ag+ | Ag The standard reduction potential for the Pb2+/Pb couple is -0.13 V, and it is +0.80 V for the Ag+/Ag couple.
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 °C. The initial concentrations of Pb2+...
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 °C. The initial concentrations of Pb2+ and Cu2+ are 0.0500 M and 1.50 M, respectively. What are the concentrations of Pb2+ and Cu2+ when the cell potential falls to 0.370 V? Cu2+ (aq) + Pb(s) + Cu(s) + Pb2+ (aq) Hint: [Pb2+] + [Cu2+] = (1.5M + 0.05M) = 1.55 M total Hint: the standard potential of Pb2+ + 2e → Pb(s) is -0.130 and the...
A voltaic cell is based on two lead half cells: Pb+2(aq) + 2 e- → Pb(s)...
A voltaic cell is based on two lead half cells: Pb+2(aq) + 2 e- → Pb(s) Eo = -0.13 v One half-cell has [Pb(NO3)2] = 0.25 M and one half-cell has [Pb(NO3)2] = 0.0020 M What is the initial potential produced by the voltaic cell. Express your answer in units of volts with 2 significant digits, but do not include the units on the submitted answer.
A voltaic cell consists of a CO2(g)｜H2C2O4(aq) electrode and a PbI2(s)｜Pb(s) electrode. Calculate the value of...
A voltaic cell consists of a CO2(g)｜H2C2O4(aq) electrode and a PbI2(s)｜Pb(s) electrode. Calculate the value of the equilibrium constant for the cell. E ○ cell for PbI |Pb 2(s) (s) = -0.365 V E ○ cell for CO2(g)|H2C2O4(aq) = -0.49 V
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 oC. The...
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 oC. The initial concentrations of Pb2+ and Cu2+ are 0.0500 M and 1.50 M, respectively. What are the concentrations of Pb2+ and Cu2+ when the cell potential falls to 0.370 V? Cu2+(ag) + Pb(s) → Cu(s) + Pb2+(ag) Hint: [Pb2+] + [Cu2+] = (1.5M + 0.05M) = 1.55 M total Hint: the standard potential of Pb2+ + 2e- → Pb(s) is -0.130 and the standard potential...
Consider the balanced equation of KI reacting with Pb(NO3)2 to form a precipitate. 2KI(aq)+Pb(NO3)2(aq)⟶PbI2(s)+2KNO3(aq) What mass...
Consider the balanced equation of KI reacting with Pb(NO3)2 to form a precipitate. 2KI(aq)+Pb(NO3)2(aq)⟶PbI2(s)+2KNO3(aq) What mass of PbI2 can be formed by adding 0.413 L of a 0.140 M solution of KI to a solution of excess Pb(NO3)2?
In the following cell, A is a standard Pb2+|Pb electrode connected to a standard hydrogen electrode. For this cell the voltmeter reading is -0.13 V. What is the chemical equation for the cell reaction? Given: Standard reduction potential of the H+/H2 and Pb2+/Pb couples are 0.00 and -0.13 V, respectively. voltmeter saltbridge 1+ Pl(s) LPH2 (g) O Pb2+(aq) + H2(g) --> Pb(s) + 2H+(aq) O Pb(s) + 2H+(aq) --> Pb2+(aq) + H2(g)
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 °C. The initial concentrations of Pb2+ and Cu2+ are 0.0500 M and 1.50 M, respectively. What are the concentrations of Pb2+ and Cu2+ when the cell potential falls to 0.370 V? Cu2+ (aq) + Pb(s) + Cu(s) + Pb2+ (aq) Hint: [Pb2+] + [Cu2+] = (1.5M + 0.05M) = 1.55 M total Hint: the standard potential of Pb2+ + 2e → Pb(s) is -0.130 and the...
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