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Practice Set-l1 SET-IV Br Br CH3 HO2C .CN 1. 4. Br Cl C OH 2. 5 OH 3. ON 6. 9ON NO2 NH2 1. N2* N(CH3)2 _OSHN OH 3. 02N...
Practice Set-llI SET-IV br Br Cl 2. 5 Cl OH NO2 NO2 3. 6 NO2 NH N(CH3)2 03s 02N 4,0N2.HIS에 OH NH2 pH <6 2 NH2 035 S...
Practice Set-llI SET-IV br Br Cl 2. 5 Cl OH NO2 NO2 3. 6 NO2 NH N(CH3)2 03s 02N 4,0N2.HIS에 OH NH2 pH <6 2 NH2 035 S03
Practice Set-llI SET-IV br Br Cl 2. 5 Cl OH NO2 NO2 3. 6 NO2 NH N(CH3)2 03s 02N 4,0N2.HIS에 OH NH2 pH
Cl 5 OHO ON -NO2 6. POSHN FOH N(CH3)2 N2 3. 1. O2N N2 N2 4. OH NH2 2. NH2 02N pH 6 2 SO3 S03 Cl 5 OHO ON -NO2 6. P...
Cl 5 OHO ON -NO2 6. POSHN FOH N(CH3)2 N2 3. 1. O2N N2 N2 4. OH NH2 2. NH2 02N pH 6 2 SO3 S03
Cl 5 OHO ON -NO2 6. POSHN FOH N(CH3)2 N2 3. 1. O2N N2 N2 4. OH NH2 2. NH2 02N pH 6 2 SO3 S03
Practice Set-IlI SET-IV CH3 HO2 1. cl 5. он NO2 6. 112. HSOİ N(CHa)2 02N 03 HS04 OH NH2 pH < 6 2. 503 Pract...
Practice Set-IlI SET-IV CH3 HO2 1. cl 5. он NO2 6. 112. HSOİ N(CHa)2 02N 03 HS04 OH NH2 pH < 6 2. 503
Practice Set-IlI SET-IV CH3 HO2 1. cl 5. он NO2 6. 112. HSOİ N(CHa)2 02N 03 HS04 OH NH2 pH
Practice Set-lll CH3 o 1. H3c-C- CHa a HaC, CH3 PY ? H-C-N H Нас + OH T CH2 2. ? CH2 he N(CH3)2 O2N HaC CH3 Phosgen...
Practice Set-lll CH3 o 1. H3c-C- CHa a HaC, CH3 PY ? H-C-N H Нас + OH T CH2 2. ? CH2 he N(CH3)2 O2N HaC CH3 Phosgene, ? (Review a 3. O-CC2 2 CO2H PY ? HaC 4. Нас OH +CH3 NH2 ? H + excess CH30H ? 6. CH(CH2)16 heat b-(CH2)1CH3 heat ? 7. CaHs-C O-CH2 + NH2-OH hydrorylarnine O-
Practice Set-lll CH3 o 1. H3c-C- CHa a HaC, CH3 PY ? H-C-N H Нас + OH T...
NH2 1. OH но 210 °C OH Na2 S204 2. 02N NaOH/H20 100 °C 3. CH3COOH...
NH2 1. OH но 210 °C OH Na2 S204 2. 02N NaOH/H20 100 °C 3. CH3COOH Na NaOH/H20 100 °C 2. CH3COOH Na2S,04 1. NaOH/H20 100 oC NO2 но 2. OH но 210 °C
1 9. Arrange the following in ng compounds in increasing (weakest to strongest) order of basicity. NH2 NH2 NO2 E. None of the above What is the product of the following sequence? 10. H3C CH3 OH о...
1 9. Arrange the following in ng compounds in increasing (weakest to strongest) order of basicity. NH2 NH2 NO2 E. None of the above What is the product of the following sequence? 10. H3C CH3 OH он Na V. A I What is the major product for the following Reaction? 11. Pd(OAc)h PPhy Et N NO2 NO2 NO2 C.Ⅲ A. I D. IV V. 12. Predict the product for the following reaction. Br 1. NaNs 2. LiAIH4 3. H20
1...
-NH2 PCC, CH2Cl2 NaBH CN OH 8 Br 1. 3 equiv. 12 4 equiv. NaOH 1....
-NH2 PCC, CH2Cl2 NaBH CN OH 8 Br 1. 3 equiv. 12 4 equiv. NaOH 1. LiAlH4 2. H2O 2. H30* 9 10 2 equiv. (CH3)2NH 1. LiAIH 2. H20 11 12 H2O 1. CH,MgCI 2. H30 13 14
g. Ph-C(O)-NH2 4 NaOH Br2 h. (HC)2CH-C(CHa)2 -> HO N(CH3)3 i. Ph-N2, CI- + CuCN -->...
g. Ph-C(O)-NH2 4 NaOH Br2 h. (HC)2CH-C(CHa)2 -> HO N(CH3)3 i. Ph-N2, CI- + CuCN --> H30* (cat) Na/ETOH j. cyclohexanone+ H2NOH Pd(OAc)2 (1 mole%) k. Ph-I + 4-O2N-C&H4-HC=CH2 Cul/Pd(PPH3)4) L. HO-CH2-CH2-CC-H +1-CH=CH-(CH2)4-CH3
The spectrochemical series is < Br<< Cl<F-<OH" <H2O <NH3 <en <NO2- < CN- The complex [Ni(Cl)c]...
The spectrochemical series is < Br<< Cl<F-<OH" <H2O <NH3 <en <NO2- < CN- The complex [Ni(Cl)c] is green and the complex [Ni(en)]2+ is violet, where en corresponds to the ethylenediamine ligand. The reason for the difference in the color of these complexes is: Select one: A. The chloride ligand is green, and the ethylenediamine ligand is violet. B. The difference in the coordination numbers of the chloride complex and the en complex. C. The difference in the oxidation states of...
Nomenclature Coordinate Complexes | <Br< SCN < Cl< O=N-0 <F <OH <C:0-(oxalato) < 0,2-<H2O <SCN <NH;...
Nomenclature Coordinate Complexes | <Br< SCN < Cl< O=N-0 <F <OH <C:0-(oxalato) < 0,2-<H2O <SCN <NH; <en (H2NCH2CH2NH2) NO2 <CN <CO Formula Name # of lone de [Cr. (NH3)3 (+20)})( triamminetriaquachromium(III) chloride [Fe(NH3).](NO2) hexaammineiron (111) nitrate [pt leng (12232 dithicyanodi(ethylenediamine)platinum(IV) chloride [Co(C204)(CO)]* Owlbunyoleation contu) lon ammonium tetraiodicuprate(II) INHO), [LUIGI Ke[Fe(ONO).] [ Fel NH3)6] hexaammineiron(III) hexahydroxochromate(III) [Co(H2NCH2CH2NH3)4](SO4)3 | +r15 4+ hy • he ºlfa wine) ¢e bal} (1) v10a4e pentaaquahydroxoiron(III) ion [Fe(H2E), GH) +2. (NH4)[Ni(O2)2(H2O)2] ammunium cinquabiscova lato) nickelate CI) AN...
Practice Set-llI SET-IV br Br Cl 2. 5 Cl OH NO2 NO2 3. 6 NO2 NH N(CH3)2 03s 02N 4,0N2.HIS에 OH NH2 pH <6 2 NH2 035 S03
Practice Set-llI SET-IV br Br Cl 2. 5 Cl OH NO2 NO2 3. 6 NO2 NH N(CH3)2 03s 02N 4,0N2.HIS에 OH NH2 pH
Cl 5 OHO ON -NO2 6. POSHN FOH N(CH3)2 N2 3. 1. O2N N2 N2 4. OH NH2 2. NH2 02N pH 6 2 SO3 S03
Cl 5 OHO ON -NO2 6. POSHN FOH N(CH3)2 N2 3. 1. O2N N2 N2 4. OH NH2 2. NH2 02N pH 6 2 SO3 S03
Practice Set-IlI SET-IV CH3 HO2 1. cl 5. он NO2 6. 112. HSOİ N(CHa)2 02N 03 HS04 OH NH2 pH < 6 2. 503
Practice Set-IlI SET-IV CH3 HO2 1. cl 5. он NO2 6. 112. HSOİ N(CHa)2 02N 03 HS04 OH NH2 pH
Practice Set-lll CH3 o 1. H3c-C- CHa a HaC, CH3 PY ? H-C-N H Нас + OH T CH2 2. ? CH2 he N(CH3)2 O2N HaC CH3 Phosgene, ? (Review a 3. O-CC2 2 CO2H PY ? HaC 4. Нас OH +CH3 NH2 ? H + excess CH30H ? 6. CH(CH2)16 heat b-(CH2)1CH3 heat ? 7. CaHs-C O-CH2 + NH2-OH hydrorylarnine O-
Practice Set-lll CH3 o 1. H3c-C- CHa a HaC, CH3 PY ? H-C-N H Нас + OH T...
NH2 1. OH но 210 °C OH Na2 S204 2. 02N NaOH/H20 100 °C 3. CH3COOH Na NaOH/H20 100 °C 2. CH3COOH Na2S,04 1. NaOH/H20 100 oC NO2 но 2. OH но 210 °C
1 9. Arrange the following in ng compounds in increasing (weakest to strongest) order of basicity. NH2 NH2 NO2 E. None of the above What is the product of the following sequence? 10. H3C CH3 OH он Na V. A I What is the major product for the following Reaction? 11. Pd(OAc)h PPhy Et N NO2 NO2 NO2 C.Ⅲ A. I D. IV V. 12. Predict the product for the following reaction. Br 1. NaNs 2. LiAIH4 3. H20
1...
-NH2 PCC, CH2Cl2 NaBH CN OH 8 Br 1. 3 equiv. 12 4 equiv. NaOH 1. LiAlH4 2. H2O 2. H30* 9 10 2 equiv. (CH3)2NH 1. LiAIH 2. H20 11 12 H2O 1. CH,MgCI 2. H30 13 14
g. Ph-C(O)-NH2 4 NaOH Br2 h. (HC)2CH-C(CHa)2 -> HO N(CH3)3 i. Ph-N2, CI- + CuCN --> H30* (cat) Na/ETOH j. cyclohexanone+ H2NOH Pd(OAc)2 (1 mole%) k. Ph-I + 4-O2N-C&H4-HC=CH2 Cul/Pd(PPH3)4) L. HO-CH2-CH2-CC-H +1-CH=CH-(CH2)4-CH3
The spectrochemical series is < Br<< Cl<F-<OH" <H2O <NH3 <en <NO2- < CN- The complex [Ni(Cl)c] is green and the complex [Ni(en)]2+ is violet, where en corresponds to the ethylenediamine ligand. The reason for the difference in the color of these complexes is: Select one: A. The chloride ligand is green, and the ethylenediamine ligand is violet. B. The difference in the coordination numbers of the chloride complex and the en complex. C. The difference in the oxidation states of...
Nomenclature Coordinate Complexes | <Br< SCN < Cl< O=N-0 <F <OH <C:0-(oxalato) < 0,2-<H2O <SCN <NH; <en (H2NCH2CH2NH2) NO2 <CN <CO Formula Name # of lone de [Cr. (NH3)3 (+20)})( triamminetriaquachromium(III) chloride [Fe(NH3).](NO2) hexaammineiron (111) nitrate [pt leng (12232 dithicyanodi(ethylenediamine)platinum(IV) chloride [Co(C204)(CO)]* Owlbunyoleation contu) lon ammonium tetraiodicuprate(II) INHO), [LUIGI Ke[Fe(ONO).] [ Fel NH3)6] hexaammineiron(III) hexahydroxochromate(III) [Co(H2NCH2CH2NH3)4](SO4)3 | +r15 4+ hy • he ºlfa wine) ¢e bal} (1) v10a4e pentaaquahydroxoiron(III) ion [Fe(H2E), GH) +2. (NH4)[Ni(O2)2(H2O)2] ammunium cinquabiscova lato) nickelate CI) AN...
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