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are not to be used to perform any calculus. x10 1. The simple supported beam ABC in Fig.(a) carries a distributed load of max

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dley (3L2- 42 M= wo (3L2-4x3) 12니 -(두=x) p EI dy + A wo 2 x= Wo A S 6L4 A = A = -wo aL 16A= -5wo |92 d(Ez) -5woL3 wo 2L 192 3 x+ 3 2L (92 Thus 2x3 5 2 142 L/2 Accrs at l= max wo d-war 12 EI 192E1 wo LY max

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