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Question 4 1 pts Consider practice question 3.4. The resistor RL is changed to 1.9 kilo-ohms. Solve part (a) of the question3.4. For the emitter follower in the figure below, given Vcc = 15 V, Vee=-15 V, Ri = 1 kQ and B= 100 for all the transistors.It is just the question 4 needs to be solved. Mind the changes in question 4.

Question 4 1 pts Consider practice question 3.4. The resistor RL is changed to 1.9 kilo-ohms. Solve part (a) of the question to find resistor R in kilo-ohms.
3.4. For the emitter follower in the figure below, given Vcc = 15 V, Vee=-15 V, Ri = 1 kQ and B= 100 for all the transistors. In the following calculations assume VCEsat= 0.2 V and VBe= 0.7 V. For this circuit find the following The value of resistor R that will establish a bias current sufficiently large to allow the largest possible output voltage swing. Include the base currents for both Q2 and Q3. The maximum output signal swing, explain your answer. The minimum and maximum emitter currents for Qi, explain your answer. (a) (b) (c) Vсс VBE R VEE VEE
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Vec= 15 V C/Ang NCESaO.2v IE EIKI V NIE= VIEn=V¢e04V SVEE S V RL had changed to 1ke ASIEPA IE=ITIL B=l00 VBE 07V RLEgKA VB-VEgiuem trumstor un AC the Source (Cumenb mrror) Curent Fi Ye= 1 Ye Vim Cre+RUp Vim Vo ERL Vin = re+R) A CB+I Via = (Bt) Tet Ruall nitanu h RL RL+ Ye aldume 3000 RLE1gKR . 19+re I-9 3 Ye+ S.7 Yet9)319 eE L9-5+kn 3 3 Te = ig-57) Tel 18K Te=-3-8k2 esitanI IE-L I 6-91KA- 4736 MA R I =-4.729- LE4.2mA IR= 4134 IIl = 4.729 mA T REHT21 IRE(A+2) P A S1- IR o2 x 4.72 mA R= 4.8226 MA

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