Question

3.1. For the BJT differential pair configuration shown below, assume the input transistor beta is very large.

Then find the differential signal vd = vB1 − vB2 sufficient to cause:

3.2. A differential amplifier resembling that below uses I = 200μA, RC = 10kohm and VCC = 3V. Assume beta is very large

3.4.For the emitter follower in the figure below, given VCC = 15 V, VEE = −15 V, RL = 1 kohm and beta = 100 for all the transistors. In the following calculations assume VCEsat = 0.2 V and VBE = 0.7 V. For this circuit find the following:

3.5

Question 1 1 pts Consider practice question 3.1. You are given that ie2 = 0.87 x l. Find the value of vd in mV. DI Question 2 1 pts Consider practice question 3.2. The bias current l is changed to 0.17 mA. Find the differential gain in part (a). DI Question 3 1 pts Consider practice question 3.2 with the original value of bias current. The resistor is changed to 8.2 kilo-ohms. What is the maximum common-mode input voltage in part (c)? D Question 4 1 pts Consider practice question 3.4. The resistor RL is changed to 1.2 kilo-ohms. Solve part (a) of the question to find resistor R in kilo-ohms. Question 5 1 pts Consider the circuit in practice question 3.5. If the input voltage vi-2.5 volts, what is the output voltage vo? Rc ic1 c2 E1 E2 ぶ! Rc Rc + Vo - Q2 Q1 Ud Vcc Ol VBE 2 Q2 Ri 03 VEE ЕЕ QP RL

Answer 1

vin, - Vge Vin2 K= <- - PA 51 + Iez -> TG TIt8 0- ?7, (- O.131. O.13 0.87 Nd = 26mv» n0.13 o.87 46. 425 mv